" (iii) "int_(0)^(3)|3x-1|dx

int_(0)^(1)|3x-1|dx=

int_(0)^(1)|3x-1|dx=

int_(0)^(3)(x+1)dx

int_(0)^(2)(3x^(2)-1)dx

int_(0)^(3)(x^(2)+1)dx

int_(0)^(3)(x^(2)+1)dx

int_(0)^(3)(x^(2)+1)dx

int_(0)^(1)3^(x)dx

int_(0)^(1)[3x]dx

Evaluate: int_(0)^(1)|5x-3|dx( ii) int_(0)^( pi)|cos x|dx( iii) int_(-5)^(5)|x-2|dx( iv )int_(-1)^(1)e^(|x|)dx(v)int_(0)^(2)|x^(2)+2x-3|dx(v)int_(1)^(4)(|x-1|+|x-2|+|x-3|)dx( vi) int_(1)^(2)|x^(3)-x|dx