[" The refractive index of a prism is "sqrt(2)" and its refractive "],[" angle is "60^(@)." If a ray emerges with the minimum angle of "],[" deviation then the angle of incidence will be "]

The refractive index of a prism is sqrt(2) and its refractive angle is 60^(@) . If a ray emerge with the minimum angle of deviation then the angle of incidence will be

The refractive index of the material of a prism is sqrt((3)/(2) and the refractive angle is 90^(@) . Calculate the angle of minimum deviation and the corresponding angle of incidence. Show that the limiting angle of incident for getting emergent ray is 45^(@) .

The refractive index of a prism for monochromatic wave is sqrt(2) and its refracting angle is 60^(@) . For minimum deviation the angle of incidence will be

The refractive index of a prism for a monochromatic wave is sqrt(2) and its refracting angle is 60^(@) for minimum deviation, the angle of indidence will be

The refractive index of a prism for a monochromatic wave is sqrt(2) and its refracting angle is 60^(@) for minimum deviation, the angle of indidence will be

The refractive index of a prism for a monochromatic wave is sqrt(2) and its refracting angle is 60^(@) for minimum deviation, the angle of indidence will be

The refractive index of the material of a prism is sqrt((3)/(2)) and the refracting angle is 90^(@) The angle of minimum deviation of the refracted ray by the prism is

A prism of refractive index sqrt(2) has refractive angle 60^(@) . Find the angle of incidence so that a ray minimum deviation.