When 45 grams of a solute is added to 900 gm of water, its vapour pressure decreased from 30 mm to 24 mm. The mole fraction of the solvent in the solution is

When 5 grams of a solute is added to 90gm of water,its vapour pressure decreased from 30mm to 27mm . The mole fraction of the solvent in the solution is

The vapour pressure of a pure liquid is 0.80 atm. When a non-volatile solute is added to this liquid, its vapour pressure drops to 0.60 atm. The mole fraction of the solute in the solution is

If mole fraction of the solvent in a solution decreases than:

The vapour pressure of pure liquid solvent A is 0.80 atm.When a non volatile substances B is added to the solvent, its vapour pressure drops to 0.60 atm. Mole fraction of the components B in the solution is:

The vapour pressure of pure liquid solvent A is 0.80 atm . When a non-volatile substance B is added to the solvent, its vapour pressure drops to 0.60 atm , the mole fraction of component B in the solution is

The vapour pressure of pure liquid solvent 0.50 atm. When a non-volatile solute B is added to the solvent, its vapour pressure drops to 0.30 atm. Thus, mole fraction of the component B is

At 300 K , when a solute is aded to a solvent ,its vapour pressure over mercury reduces from 50 mm to 45 mm . The value of mole fraction of solute wil be _____.

Vapour pressure of benzene at 30^(@)C is 121.8 mm. When 15 g of a non-volatile solute is dissolved in 250 g of benzene its vapour pressure decreased to 120.2 mm. The molecular weight of the solute is (mol. Weight of solvent = 78)