" Escape velocity of a body from earth is "11.2km/s" .Escape velocity,when thrown at an angle of "45^(0)" from horizontal will be "

The escape velocity of a body from the surface of earth is

The escape velocity of a projectile from the earth is approximately

Escape velocity of a rocket is 11.2 km/sec. It is released at an angle of 45^(@) . Its escape velocity is

The escape velocity of a body from the earth's surface, v_("esc")= ……….. .

The escape velocity of a body from the surface of the earth is equal to

Escape velocity on the surface of earth is 11.2 km/s . Escape velocity from a planet whose mass is the same as that of earth and radius 1/4 that of earth is

The mass of a planet is four times that of the earth and its radius is double the radius of earth . The escape velocity of a body from the earth is 11.2xx 10^(3) m/s. Find the escape velocity of a body from the plant .

The escape velocity of a body from earth's surface is v_e . The escape velocity of the same body from a height equal to 7R from earth's surface will be

The escape velocity of a body from the earth is V_(e) . The escape velocity of a planet whose mass and radius are twice those of the earth is