According to parallelogram law of vectors the magnitude of resultant of two vectors `bar(A)` and `bar(B)` is

Assertion: A vector qunatity is a quantity that has both magnitude and a direction and obeys the triangle law of addition or equivalentyly the parallelogram law of addition. Reason: The magnitude of the resultant vector of two given vectors can never be less than the magnitude of any of the given vector.

Assertion : A vector quantity is a quantity that has both magnitude and a direction and obeys the triangle law of addition and equivalently the parallelogram law of addition. Reason : The magnitude of the resultant vector of two given vectors can never be less than the magnitude of any of the given vector.

If sqrt(A^(2)+B^(2)) represents the magnitude of resultant of two vectors (A+ B) and (A - B),then the angle between two vectors is

State parallelogram law of vector addition. Find analytically the magnitude and direction of resultant vector. Apply it to find the resultant when, (i) Two vectors are parallel to each other (ii) Two vectors are perpendicular to each other

State parallelogram law of vectors addition .Find analytcallly the magnitude and direction of resultant vector, When (i) two vectors are parallel to each other (ii) two vectors are perpendicular to each other.

A vector of magnitude 3 , bisecting the angle between the vectors bar(a)=2i+j-k and, bar(b)=i-2j+k is-

Let bar(a),bar(b),bar(c) be vectors of equal magnitude such that the angle between bar(a) and bar(b) is alpha,bar(b) and bar(c) is beta and bar(c) and bar(a) is gamma. Then the minimum value of cos alpha+cos beta+cos gamma is

Asserion: Magnitude of the resultant of two vectors may be less than the magnitude of either vector. Reason: The resultant of two vectors is obtained by means of law of parallelogram of Vectors.