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If y=x^(n-1)lnx then x^2y2+(3-2n)x y1 i...

If `y=x^(n-1)lnx` then `x^2y_2+(3-2n)x y_1` is equal to `-(n-1)^2y` (b) `(n-1)^2y` `-n^2y` (d) `n^2y`

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