Magnitude of K.E. in an orbit is equal to

In hydrogen atom radius of the first orbit is 0.53 Å . Minimum work required to free the electron, given its K.E in the orbit is half the magnitude of P.E in the orbit.

The average K.E. of one mole of an ideal gas in calories is equal to

If the angular momentum of an electron in an orbit is J then the K.E. of the electron in that orbit is

At what distance from mean position is K.E equal to P.E?

If the K.E. of a satellite revolving around the earth in any orbit is doubled then what will happen to satellite?

The average K.E. of one mole of any gas is equal to _____.

The magnitude of the P.E. of the electron in the first orbit of the bohr's atom is E. What is its K.E. ? S

In the Bohr model of the atom (i) the radius of the n^(th) orbit is proportional to n^(2) (ii) the total energy of the electron in n^(th) orbit is inversely proportional to n (iii) the angular momentum of the electron in an orbit is an integral multiple of h//2 pi (iv) the magnitude of the P.E. of the electron in an orbit is gt its K.E.