In the figure each cell has an emf of 1.5 V and internal resistnce of `0.40 Omega` Calculate :

(i) current I
(ii) potential differnce across A and B.

The lamp of flash light is 1.5 Omega . It uses 3 cells each of 1.5 V and internal resistance 0.25 Omega . What is the net potential difference across the lamp ?

A battery has six cells in series. Each has an emf 1.5 V and internal resistance 1 ohm. If an external load of 24Omega is connected to it. The potential drop across the load is

Two cell with unequal emfs of 2V and 3V are connected as shown in the figure. If each cell has an internal resistance r = 0.45 Omega and external resistance is of 4 Omega . Then, Potential drop across resistor 4 Omega is

A current of 2.0 A passes through a cell of emf 1.5 V having internal resistance of 0.15 Omega . The potential difference (measured in volt) across both the terminals of the cell is