`lim_(x->0)(ln(1+x^2+x^4)/((e^x-1)x)`

lim_(x->0)(e^log(2^x-1)^x-(2^x-1)^(x)*sinx))/(e^(xlogx)) is equal to

lim_(xto0)(log(1+3x^(2)))/(x(e^(5x)-1)) =

Evaluate (lim)_(x->0)((log)_e x)/(x-1)

Evaluate the following limit : lim_(x rarr 0)(log(1+x))/(e^x-1) .

Evaluate : lim_(x rarr 0)log(1+5 x)/(e^(2x)-1)

a=lim_(x rarr0)(ln(cos2x))/(3x^(2)),b=lim_(x rarr0)(sin^(2)2x)/(x(1-e^(x))),c=lim_(x rarr1)(sqrt(x)-x)/(ln x)

lim_(x rarr0)(ln(1+x)^(1+x))/(x^(2))-(1)/(x)

lim_(x rarr0)[(ln(1+x)^(1+x))/(x^(2))-(1)/(x)]

lim_(x rarr0)(log(1-(x)/(2)))/(x)