If `alpha,beta` are roots of `x^2+3x+1=0` then

If alpha, beta are the roots of x^(2)+3x+1=0 , then the equation whose roots 2-alpha, 2-beta is

If alpha, beta are the roots of x^(2)+3x+1=0 , then the equation whose roots 2-alpha, 2-beta is

If alpha, beta are the roots of x^(2)-3x+1=0 , then the equation whose roots are (1/(alpha-2),1/(beta-2)) is

If alpha, beta are the roots of x^(2)-3x+1=0 , then the equation whose roots are (1/(alpha-2),1/(beta-2)) is

If alpha, beta are the roots of x^(2)-3x+1=0 , then the equation whose roots are (1/(alpha-2),1/(beta-2)) is

If alpha, beta are the roots of x^(2)-3x+1=0 , then the equation whose roots are (1/(alpha-2),1/(beta-2)) is

If alpha, beta are the roots of x^(2)-3x+1=0 , then the equation whose roots are (1/(alpha-2),1/(beta-2)) is

If alpha,beta are roots of x^(2)-3x+a=0,a in R and alpha<1

If alpha,beta are roots of x^2-3x+a=0 , a in R and alpha <1< beta then find the value of a.

If alpha,beta are roots of x^2-3x+a=0 , a in R and alpha <1< beta then find the value of a.