If the lines `x+(a-1)y=1` and `2x+1a^(2)y=1` there `ainR-{0,1}` are perpendicular to each other, Then distance of their point of intersection from the origin is

If the lines x+(a-1)y=1 and 2x+1a^(2)y=1 there a in R-{0,1} are perpendicular to each other,Then distance of their point of intersection from the origin is

If the two lines x+(a-1)y=1 and 2x+a^(2)y=1 , (a in R-{0}) are perpendicular , then the distance of their point of intersection from the origin is

Show that lines x-2y-7=0 and 2x+y+1=0 are perpendicular to each other. Find their point of intersection.

If the lines x+(a-1)y+1=0 and 2x+a^(2)y-1=0 are perpendicular,then find the value of a.

If the lines x+(a-1)y+1=0 and 2x+a^2y-1=0 are perpendicular, then find the value of adot

The square of the distance of the point of intersection of the line 6x^2-5xy-6y^2+x+5y+1=0 from the origin is

If p_(1),p_(2) are the perpendicular distance from the origin to the two straight lines which are perpendicular to each other, then the locus of the point of intersection of the perpendicular lines is

Show that the lines x=-y =2z " and " x+2 =2y -1 =-z +1 are perpendicular to each other .

If p_1,p_2 are the perpendicular distance from the origin to the two perpendicular to each other, then the locus of the point of intersection of the perpendicular lines is

Find the point of intersection of the lines 4x+8y-1=0, 2x-8y+1=0