निम्नलिखित फलनों का आलेख खींचिए -
`f(x)={(-x", जब "xlt0),(x", जब "0lexle1),(2-x", जब "xgt1.):}`

If f(x)={{:(x",",0lexle1),(x+a",",xgt1):} then

Discuss the continuity of the function f, where f is defined by : f(x)={{:(2x", if "xlt0),(0", if "0lexle1),(4x", if "xgt1):}

If f(x)={(x-1",",xlt0),(1/4",",x=0),(x^2",",xgt0):} , then

For the function f(x)={{:(x+2", "xgt0),(x-2", "xlt0):}

Find the left and right hand limits of the function at the point 'a' mentioned against them. Hence check whether the function have limits at those points. f(x)={{:(1" if "xlt0),(2x+1" if "0lexlt1),(3x" if "xgt1):},a=1

Examine continuity at the given point of the function f defined by f(x)={(-x,xlt0),(x,0lexle1,),(2-x,xgt1,):} at x=0,1

Discuss the continuity of the function f(x)={(2 x , if , xlt0),( 0, if, 0 le x le 1),( 4 x, if , xgt1):}.

f:RrightarrowR be defined by f(x)={((a-bcos2x)/x^2, xlt0),(x^2+cx+2,0lexle1),(2x+1,xgt1):} If f is continuous and M is the number of points where it is not differentiable then m+a+b+c