Que. 27: on y = e * (0,1) The equation of the tangent to the point. Is.

The equation of the tangent to the curve y = e^(2x) at (0,1) is

Equation of the tangent to the curve y=e^(x) at (0,1) is

The equation of tangent to y=cos x at (0, 1) is ………..

The equation of the tangent to the curve y=4xe^(x) at (-1,(-4)/e) is

Fill in the blanks: The equation of the tangent to the curve y = e^(2x) at the point (0,1) is__________.

Find the equation of the tangent to the curve y=sec x at the point (0,1)

The equation of the tangent to the curve y=sec x at the point (0,1) is (a) y=0 (b) x=0 (c) y=1 (d) x=1

Find the equation of the tangent and the normal at the point (0, -1) to the curve 5x^2+3y^2+2x+4y+1=0

The equation of the tangent to the curve y=1-e^((x)/(2)) at the point of intersection with the y -axis,is