" 6."1-i sqrt(3)" ."

If i=sqrt(-)1, then 4+5(-(1)/(2)+(i sqrt(3))/(2))^(334)+3(-(1)/(2)+(i sqrt(3))/(2))^(365) is equal to (1)1-i sqrt(3)(2)-1+i sqrt(3)(3)i sqrt(3)(4)-i sqrt(3)

The argument of (1-i sqrt(3))/(1+i sqrt(3))=

Simplify : (i)" "(-2i)((1)/(6)i)" "(ii)" "(-i)(3i)((-1)/(6)i)^(3)" "(iii)" "4 sqrt(-4)+5 sqrt(-9)-3 sqrt(-16)

Let z_(1)=(2sqrt(3)+ i6sqrt(7))/(6sqrt(7)+ i2sqrt(3))" and "z_(2)=(sqrt(11)+ i3sqrt(13))/(3sqrt(13)- isqrt(11)) . Then |(1)/(z_1)+(1)/(z_2)| is equal to

The amplitude of (1+i sqrt(3))/(sqrt(3)+i) is (pi)/(3) b.-(pi)/(6) c.(pi)/(3) d.(pi)/(6)

(sqrt(-2))(sqrt(-3)) is equal to sqrt(6)b.-sqrt(6)c.i sqrt(6)d* none of these