Find the number of photons entering the pupil of our eye per second corresponding to the minimum internsity of white light that we humans can perceive `(-10^(-10) Wm^(-2))`. Take the area of the pupil to be about `0.4 cm^(2)`, and the average frequency of white light to be about `6xx10^(14) Hz`.

Estimating the following numbers should be interesting. The number tells you why our eye can never count photons, even in barely detetable light. The number of photons entering the pupil of our eye per second corresponding to the minimum intensity of white light that we humans can perceive (~10^-10 Wm^-2) . Take the area of the pupil to be about 0.4 cm^2 , and the average frequency of white light to be about 6 xx 10^14 Hz .

Estimating the following number should be interesting. The number tells you why our eye can never 'count photons', even in barely detectable light. The number of photons entering the pupil of our eye per second corresponding to the minimum intensity of white light that we humans can perceive (~10^(-10) W. m^(-2)) . Take the area of the pupil to be about 0.4 cm^(2) and the average frequency of the white light to be about 6xx10^(14) Hz.

Estimating the following two numbers should be interesting. The first number will tell you why radio engineers do not need to worry much about photons! The second number tells you why our eye can never ‘count photons’, even in barely detectable light. (a) The number of photons emitted per second by a Medium wave transmitter of 10 kW power, emitting radiowaves of wavelength 500 m. (b) The number of photons entering the pupil of our eye per second corresponding to the minimum intensity of white light that we humans can perceive (~10^(-10) W m^(-2)) . Take the area of the pupil to be about 0.4 cm2 , and the average frequency of white light to be about 6 xx 10^(14) Hz

Estimating the following two numbers should be interesting. The first number will tell you why radio engineers do not need to worry much about photons! The second number tells you why our eye can never ‘count photons’, even in barely detectable light. (a) The number of photons emitted per second by a Medium wave transmitter of 10 kW power, emitting radiowaves of wavelength 500 m. (b) The number of photons entering the pupil of our eye per second corresponding to the minimum intensity of white light that we humans can perceive (~10^(-10) W m^(-2)) . Take the area of the pupil to be about 0.4 cm2 , and the average frequency of white light to be about 6 xx 10^(14) Hz

Estimate the following the following two numbers should be interesting. The first number will tell you why radio engieers do not need to worry much about a photons. The second number tells you why our eye can never "count photon" even in barely detectable light. (i) The number of photons emitted per second by a MW transmitter of 10kW power emitting radiowaves of length 500m. (ii) The number of photons entering the pupil of our eye per second corresponding to the minimum intensity of white light that we humans can precieve (~10^(-10)Wm^(-2)) . Take the area of the pupil to be about 0.4cm^(2) , and the average frequency of white light to be about 6xx10^(4)Hz. (h=6.6xx10^(-34)J)

The wave number of a wave of light is 2.0xx10^(14)cm^(-1) . The frequency of this light is