A solid A dissociates to give B and C gases as shown, `A(s) hArr 2B(g)+3C(g)`
At equilibrium some B(g) is introduced keeping volume constant so that pressure of B of new equilibrium becomes equal to `8/(5sqrt2)` times original total pressure calculate ratio of initial equilibrium pressure of C to that of its final pressure

Solid Ammonium carbamate dissociates as: NH_(2)COONH_(4)(s)hArr2NH_(3)(g)+CO_(2)(g). In a closed vessel, solid ammonium carbonate is in equilibrium with its dissociation products. At equilibrium, ammonia is added such that the partial pressure of NH_(3) at new equilibrium now equals the original total pressure. Calculate the ratio of total pressure at new equilibrium to that of original total pressure. Also find the partial pressure of ammonia gas added.

Solid Ammonium carbamate dissociates as: NH_(2)COONH_(4)(s)hArr2NH_(3)(g)+CO_(2)(g). In a closed vessel, solid ammonium carbonate is in equilibrium with its dissociation products. At equilibrium, ammonia is added such that the partial pressure of NH_(3) at new equilibrium now equals the original total pressure. Calculate the ratio of total pressure at new equilibrium to that of original total pressure. Also find the partial pressure of ammonia gas added.

Solid Ammonium carbamate dissociates as: NH_(2)COONH_(4)(s)hArr2NH_(3)(g)+CO_(2)(g). In a closed vessel, solid ammonium carbamate is in equilibrium with its dissociation products. At equilibrium, ammonia is added such that the partial pressure of NH_(3) at new equilibrium now equals the original total pressure. Calculate the ratio of total pressure at new equilibrium to that of original total pressure.

A(s)hArr2B(g)+C(g) The above equilibrium was established by initially taking A(s) only. At equilibrium, B is removed so that its partial pressure at new equilibrium becomes 1//3^(rd) of original total pressure. Ratio of total pressure at new equilibrium and at initial equilibrium will be :

A(s)hArr2B(g)+C(g) The above equilibrium was established by initially taking A(s) only. At equilibrium, B is removed so that its partial pressure at new equilibrium becomes 1//3^(rd) of original total preswsure. Ratio of total pressure at new equilibrium and at initial equilibrium will be :

For the reaction AB(g)hArrA(g)+B(g) , at equilibrium AB is 20% dissociated at a total pressure of P, The equilibrium constant K_(p) is related to tha total pressure by the expression