a^(2)b^(2)-6abc+9c^(2)

Factorise : 12abc -6a^(2) b^(2) c^(2) + 3a^(3) b^(3) c^(3)

a +b+c= 3, (1)/(a) + (1)/(b) + (1)/(c )=2 a^(2) + b^(2) + c^(2)=6 find abc=?

If a + b + c = 6, a^(2) + b^(2) + c^(2) = 30 and a^(3) + b^(3) + c^(3) = 165 , then the value of 4abc is:

If =det[[abc,b^(2)c,c^(2)babc,c^(2)a,ca^(2)abc,c^(2)a,ca^(2)abc,a^(2)b,b^(2)a]]=0,(a,b,c in R) and a+b+c,=0a+b+c,=0

If a,b,c are real and distinct,then show that a^(2)(1+b^(2))+b^(2)(1+c^(2))+c^(2)(1+a^(2))>6abc

If a^(2)+9b^(2)+25c^(2)=abc((15)/(a)+(5)/(b)+(3)/(c)), then a,b,c are in

In a Delta ABC if 9(a^(2)+b^(2))=17c^(2) then the value of the (cot A+cot B)/(cot C) is

If a+b+c=9,a^(2)+b^(2)+c^(2)=27 and a^(3)+b^(3)+c^(3)=81 then find the value of 3abc.

If a+b+c=9 and a^(2)+b^(2)+c^(2)=35, find the value of a^(3)+b^(3)+c^(3)-3abc

In any triangle ABC,(a^(2)+b^(2)+c^(2))/(R^(2)) has the maximum value of 3 (b) 6^(R)(c)9(d) none of these