" 14.If "A=[[cos theta,-sin theta],[sin theta,cos theta]]," then Adj "A" is "

" (1) "|[cos theta,-sin theta],[sin theta,cos theta]|

If A= [[cos theta,-sin theta],[sin theta,cos theta]] ,then Adj A is (a) [[cos theta,-sin theta],[cos theta,sin theta]] (b) [[1,0],[0,1]] (c) [[cos theta,sin theta],[-sin theta,cos theta]] (d) [[-1,0],[0,-1]]

If A=[(-cos theta, sin theta),(sin theta, cos theta)] then IAI=

(i) |(cos theta,-sin theta),(sin theta,cos theta)|

If A = [[cos theta, sin theta],[-sin theta, cos theta]] , then what is A^(-1) ?

Evaluate |[cos theta, -sin theta], [sin theta, cos theta]|

If A=[{:(cos theta, sin theta),(-sin theta, cos theta):}] then "A A"^(T) is :

cos theta/(1+sin theta)=(1-sin theta)/cos theta

A = [(cos theta,-sin theta),(-sin theta,-cos theta)] then find A^(-1) .

cos theta+sin theta=cos2 theta+sin2 theta