`,x-y=-1, 3x-2y=12`

x+2y=-1,2x-3y=12

Find the solution of the pair of equations: x-y+1=0, 3x+2y-12=0

Draw the graph of the following equation and determine the vertices of the triangle. x-y+1=0, 3x+2y-12=0, y=0

Solve for x and y: 2x - 3y-13 =0 , 3x -2y+12 =0

(3) x+2y=-1;2x-3y=12

If 3x-2y=11 and x y=12 , find the value of 27\ x^3-8y^3

The centres of 3 circles x^2+y^2 =1, x^2+y^2 +6x-2y=1, x^2+y^2-12x+4y=1 are :

Solve the following system of equations by matrix method : 5x+7y+2=0 4x+6y+3=0 5x+2y=3 3x+2y=5 3x+4y-5=0 x-y+3=0 3x+y=19 3x-y=23 3x+7y=4 x+2y=-1 3x+y=7 5x+3y=12

Draw the graph of each of the following : (i)(x)/(3)+(y)/(5)=1 , (ii) (2x+6)/(5)=y-1 , (iii) 3x+4y=12 , (iv)3x-y=2

2x+3y=12;x-y=1