If `|f(x_1) - f(x_2)| le (x_1 - x_2)^(2), AA x_1 , x_2 in R`. Find the equation of tangent to the curve `y = f(x)` at the point `(1, 2)`.

If |f(x_2)-f(x_1)|le(x_2-x_1)^2AAx_1,x_2inR, then the equation of tangent to the curve y = f(x) at the point (1,2) is

If |f(x_(1))-f(x_(2))|<=(x_(1)-x_(2))^(2), for all x_(1),x_(2)in R, then the equation of tangent to the curve y=f(x) at the point (1,2) is a.y=2 b.y=3 c.x=2 d.x=3

if |f(x_1)-f(x_2)|<=(x_1-x_2)^2 Find the equation of tangent to the curve y= f(x) at the point (1, 2).

if |f(x_1)-f(x_2)|<=(x_1-x_2)^2 Find the equation of tangent to the curve y= f(x) at the point (1, 2).

if |f(x_1)-f(x_2)|<=(x_1-x_2)^2 Find the equation of tangent to the curve y= f(x) at the point (1, 2).

if |f(x_1)-f(x_2)|<=(x_1-x_2)^2 Find the equation of gent to the curve y= f(x) at the point (1, 2).

if |f(x_(1))-f(x_(2))|<=(x_(1)-x_(2))^(2) Find the equation of gent to the curve y=f(x) at the point (1,2).

A polynomial function f(x) satisfies the condition f(x+1)=f(x)+2x+1. Find f(x) if f(0)=1 Findalso the equations of the pair of tangents from the origin on the curve y=f(x) and compute the areaenclosed by the curve and the pair of tangents.

If f(x)+2f(1-x)=x^(2)+1,AA x in R, then the range of f is :