A body moves between two points A and B which are at a distance a and b from the point O in the same straight line OAB. Then the amplitude of oscillation is

The sum of angles of elevation of the top of a tower from two points distance a and b from the base and in the same straight line with it is 90^@ . Then the height of the tower is :

If the angles of elevation of the top of a tower from two points at distances a and b from the base and in the same straight line with it are complementary then the height of the tower is

The angles of elevation of the top of a tower from two points at a distances a meter and b metres from the base of the tower and in the same straight line with it are complementary. Prove that the height of the tower is sqrt(a b) metres.

The angle of elevation of the top of a tower from the point P and Q at distance of a and b respectively from the base of the tower and in the same straight line with it are complementary .The height of the tower is

If the angles of elevation of a tower from two points distant a and b from the base and in the same straight line with it are complementary, then the height of the tower is (a) a b (b) sqrt(a b) (c) a/b (d) sqrt(a/b)

A body moves along a straight line OAB simple harmonically. It has zero velocity at the points A and B which are at distances 'a' and b' respectively from 0' and has velocity 'V' when halfway between them then the period of SHM

If the angles of elevation of a tower from two points distance a and b (agtb) from its foot and in the same straight line from it are 30^@ and 60^@ , then the height of the towers

The distance between two consecutive points which are in the same state of oscillation is

A particle moves with a simple harmonic motion in a straight line, in the first second starting from rest it travels a distance a and in the next second it travels a distance b in the same direction. The amplitude of the motion is