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With usual notations, in triangle A B C ...

With usual notations, in triangle `A B C ,acos(B-C)+bcos(C-A)+c"cos"(A-B)` is equal to(a) `(a b c)/R^2` (b) `(a b c)/(4R^2)` (c) `(4a b c)/(R^2)` (d) `(a b c)/(2R^2)`

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