In a triangle ABC, if the sides a,b,c, are roots of `x^3-11 x^2+38 x-40=0,` then find the value of `(cosA)/a+(cosB)/b+(cosC)/c`

In DeltaABC , if the sides a,b,c are the roots of x^(3)-11x^(2)+38x-40=0 then the value of (cosA)/(a)+(cosB)/(b)+(cosC)/(c)=

In a DeltaABC , if the sides a, b, c are the roots of the equation x^(3)-11x^(2)+38x-40=0 , then (cosA)/a+(cosB)/b+(cosC)/c=

In a Delta ABC, the side a, b, and c are such that they are roots of x^(3) -11x ^(2) +38x -40=0. Then the value of (cos A)/(a )+ (cos B)/(b)+ (cos C)/(c ).

If the sides a, b, c of a triangle ABC are the roots of the equation x^(3)-13x^(2)+54x-72=0 , then the value of (cosA)/(a)+(cosB)/(b)+(cosC)/(c ) is equal to :

If the sides a, b, c of a triangle ABC are the roots of the equation x^(3)-13x^(2)+54x-72=0 , then the value of (cosA)/(a)+(cosB)/(b)+(cosC)/(c ) is equal to :

If in a triangle ABC a,b,are roots of the equation x^(3)-11x^(2)+38x-40=0 then sum(cos A)/(a) equal to:

(a+b+c)(cosA+cosB+cosC)

In a triangle ABC, the side a,b,c are such that they are the roots of then (cosA)/a+(cosB)/b+(cosC)/c=

If any triangle ABC, a=18,b=24,c=30 cosA,cosB,cosC