The horizontal range of a projectile is `2 sqrt(3)` times its maximum height. Find the angle of projection.

The horizontal range of a projectile is 2sqrt(3) time its maximum height. Find the angle of projection .

The horizontal range of a projectile is 4 sqrt(3) times its maximum height. Its angle of projection will be

The horizontal range of a projectile is 4 sqrt(3) times its maximum height. Its angle of projection will be

The horizontal range of a projectile is 4 sqrt(3) times its maximum height. Its angle of projection will be

The horizontal range of projectile is 4sqrt(3) times the maximum height achieved by it, then the angle of projection is

The maximum range of a projectile is 2/sqrt3 times its actual range. What is the angle of projection for the actual range?

The horizontal range is four times the maximum height attained by a projectile. The angle of projection is