it `P` is equidistant from `A(-7.-5)` and `B(-9, -1)` and its abscissa is equal to its ordinate, find the coordinates of the point `P.`

A point P is equidistant from A (3, 1) and B (5, 3) and its abscissa is twice its ordinate, then its co-ordinates are.

The point P is equidistant from A(1,3) , B(-3,5) and C(5,-1) ,then PA is equal to

If P be a point equidistant from points A (3,4) and B (5,-2) and area of DeltaPAB is 10 square units, then find the co-ordinates of point P.

If P be a point equidistant from points A (3,4) and B (5,-2) and area of DeltaPAB is 10 square units, then find the co-ordinates of point P.

The point P is equidistant from A(1,3),B(-3,5) and C(5,-1), then PA is equal to

The point P is equidistant from A(1,3) B(-3,5) and C(5,-1) . Then P A=

The point whose abscissa is equal to its ordinate and which is equidistant from A(4,0) and B(0,5) is

The point whose abscissa is equal to its ordinate and which is equidistant from A(-1, 0) and B(0, 5) is

A point P on y-axis is equidistant from the points A(-5,4) and B(3,-2). Its co- ordinates are