In the mixture of `(NaHCO_(3)+Na_(2)CO_(3))` volume of HCl required is x mL with phenolphthalein indicator and then y mL with methyl orange indicator in same titration Hence, volume of HCl for complete reaction of `Na_(2)CO_(3)` is

In the mixture of (NaHCO_3 + Na_2CO_3) , volume of HCI required is x mL with phenolphthalein indicator and y mL with methly orange indicator in the same titration. Hence, volume of HCI for complete reaction of Na_2CO_3 is : (a) 2x (b) y (c) x/2 (d) (y-x)

In the mixture of NaHCO_(3) and Na_(2)CO_(3) , the volume of a given HCl required is x mL with phenolphthalein indicator and further y mL required with methyl orange indicator. Hence volume of HCl for complete reaction NaHCO_(3) is

In the mixture of NaHCO_(3) and NaCO_(3) , volume of a given HCl required is x ml with phenolphathalein indicator and further y mL is required with methyl orange indicator. Hence volume of HCl for complete reaction of NaHCO_(3) present in the original mixture is

A sample of NaHCO_(3) + Na_(2)CO_(3) required 20 ml of HCl using phenolphthalein as indicator and 35ml more required if methyl orange is used as indicator . Then molar ratio of NaHCO_(3) to Na_(2)CO_(3) is

A sample of NaHCO_(3) + Na_(2)CO_(3) required 20 ml of HCl using phenolphthalein as indicator and 35ml more required if methyl orange is used as indicator . Then molar ratio of NaHCO_(3) to Na_(2)CO_(3) is

A mixutre solution of KOH and Na_2CO_3 requires 15 " mL of " (N)/(20) HCl when titrated with phenolphthalein as indicator.But the same amoound of the solutions when titrated with methyl orange as indicator requires 25 " mL of " the same acid. Calculate the amount of KOH and Na_2CO_3 present in the solution.

40 mL of 0.05 M solution of sodium sesquicarbionate (Na_(2)CO_(3). NaHCO_(3).2H_(2)O) is titrated against 0.05 M HCl solution. X ml of HCl solution is used when phenophthalein is the indicator and y ml of HCl is used when methyl orange is the indicator in two separate titrations Hence (y-x) is