The distance x covered in time t by a body having initial velocity u and having constant acceleration a is given by x ` = ut + (1 ) /( 2 ) at ^ 2 ` . This

The distance x covered in time t by a body having initial velocity v_(0) and having a constant acceleration a is given by x = v_(0)t + (1//2)at^(2) This result follows from

The distance x covered in time t by a body having initial velocity v_(0) and havig a constant acceleration a is given by x=v_(0)t+((1)/(2))at^(2) . This result follows from:-

The distance x covered in time t by a body having initial velocity v_(0) and havig a constant acceleration a is given by x=v_(0)t+((1)/(2))at^(2) . This result follows from:-

Write an expression for the distance S covered in time t by a body which is initially at rest and starts moving with a constant acceleration a.

The velocity of a particle at an instant "t" is v=u+at ,where u is initial velocity and a is constant acceleration.The v -t graph are

A body is moving with an initial velocity u and a uniform acceleration a. Find the distance covered by the body in nth second.

If a particle starts moving along a straight ine withinitial velocity u under contact acceleration a, its displacement with time is given by the relation x=ut+(1)/(2)at^2 Q. The concerned deviation of positon time realtion w.r.t will be. Differentiation of above result w.r.t. t will be