बिन्दु (1 , -2) की वृत्त `x^(2) + y^(2) + 4x -2y - 1 = 0 ` के सापेक्ष स्थिति ज्ञात कीजिए |

2x-y=4,x-2y+1=0

If 9x^2+y^2=37 and xy = 2 , x, y> 0 , then the value of (27x^3+y^3) is : यदि 9x^2+y^2=37 और xy = 2 , x, y> 0 , तो (27x^3+y^3) का मान ज्ञात कीजिए ।

A circle S cuts three circles x^(2) + y^(2) - 4x - 2y + 4 = 0 , x^(2) + y^(2) - 2x - 4y + 1 = 0 " and " x^(2) + y^(2) + 4x + 2y + 1 = 0 orthogonally . Then the radius of S is

Prove that the centres of the circle x^(2) + y^(2) - 4x - 2y + 4 = 0, x^(2) + y^(2) - 2x - 4y + 1 = 0 and x^(2) + y^(2) + 2x - 8y + 1 = 0 are collinear. More over prove that their radii are in geometric pregression.

The circle x^2 + y^2 - 2x - 4y + 1 = 0 and x^2 + y^2 + 4x + 4y - 1 = 0

The equation of the incircle of the triangle formed by the coordinate axes and the line 4x + 3y - 6 = 0 is (A) x^(2) + y^(2) - 6x - 6y - 9 = 0 (B) 4 (x^(2) + y^(2) - x - y) + 1 = 0 (C) 4 (x^(2) + y^(2) + x + y) + 1 = 0 (D) 4 (x^(2) + y^(2) - x - y ) - 1 = 0

The equation of the circle which cuts orthogonally the three circles x^(2) + y^(2) + 4x + 2y + 1 = 0 , 2x^(2) + 2y^(2) + 8x + 6y - 3 = 0 , x^(2) + y^(2) + 6x - 2y - 3 = 0 is

Let find the radical and centre of the circles x^2 + y^2 - 2x + 6y = 0 " ___"(1) x^2 + y^2 - 4x - 2y + 6 = 0 " ____"(2) and x^2 + y^2 -12x + 2y + 3 = 0 "___"(3)