((2x)/(7)-(y)/(2))^(2)-((2x)/(7)+(y)/(2))^(2)

Simplify : (i) (5x - 9y) - (-7x + y) (ii) (x^(2) -x) -(1)/(2)(x - 3 + 3x^(2)) (iii) [7 - 2x + 5y - (x -y)]-(5x + 3y -7) (iv) ((1)/(3)y^(2) - (4)/(7)y + 5) - ((2)/(7)y - (2)/(3)y^(2) + 2) - ((1)/(7)y - 3 + 2y^(2))

Solve:(1)/(2(2x+3y))+(12)/(7(3x-2y))=(1)/(2)(7)/(2x+3y)+(4)/(3x-2y)=2 where 2x+3y!=0 and 3x-2y!=0

If x=2 and y=3, then find the values of (i) (2x+3y)/(4x-3y) " "(ii) (2x^(2)-7x+2y)/(2y^(2)-7y+2x)

Solve for x and y if [(x^(2)),(y^(2))]+2[(2x), (3y)]=3[(7),(-3)]

7(x-2y)^(2)-25(x-2y)+12

If y=(x^(7/2)+x^(-1/2))/(x^(7/2)-x^(-1/2)) , then (dy)/(dx)=

Comprehension (Q.5 & 6 ) Let AB be any chord of the circle x^(2)+y^(2)-2x-6y-6=0 which subtends a right angle at the point (2, 4).Locus of mid point of AB is x^(2)+y^(2)-7y-16=0x^(2)+y^(2)-3x-7y+7=0x^(2)+y^(2)+3x+7y-16=0x^(2)+y^(2)+3x+7y-7=0

Simplify : ( 3y ( x - y) - 2x ( y -2x))/( 7x ( x - y) - 3 ( x ^(2) - y ^(2)))

(dy)/(dx)=(x+y+7)/(2x+2y+3)

If log_((x+y))(x - y) = 7 , then the value of log_((x^(2)-y^(2)))(x^(2)+2xy+y^(2)) is ______.