in `j.j` thomson's method ,electric field of intensity `E`, magnetic field of induction `B` and velocity `V` of the electron were in mutually perpendicular direction . The condition for velocity is

E/B. Find the unit. (E = electric field intensity, B = magnetic field intensity)

The electric field intensity E, current density J and conductivity delta are related as—

In a certain region of space electric field E and magnetic field B are perpendicular ot each other and an electron enters region perpendicular to the direction of B and E both and moves undeflected, then velocity of electron is

An electron enters a region where magnetic field (B) and electric field (E ) are mutually perpendicular, then

An electron enters a region where magnetic field (B) and electric field (E ) are mutually perpendicular, then

In a certain region of space electric field E and magnetic field B are perpendicular to each other and an electron enters region perpendicular to the direction of B and E both and moves undeflected, then velocity of electron is (a) (|E|)/(|B|) (b) ExxB (c) (|B|)/(|E|) (d) E.B

An electron enter a region when magnetic field (B) and electric field (E) are mutually perpendicular, then

An electron of mass m and charge e is fired perpendicular to a uniform electric field of intensity E with an initial velocity u. If the electron traverses a distance x in the field in the direction of firing, find the transverse displacement y it suffers.