The new resistance of wire of `R Omega`, whose radius is reduced half, is

The resistance of a wire is 10 ohm. The resistance of a wire whose length is twice and the radius is half, if it is made of same material is

The resistance of a wire R Omega . The wire is stretched to double its length keeping volume constant. Now, the resistance of the wire will become

The resistance of a wire R Omega . The wire is stretched to double its length keeping volume constant. Now, the resistance of the wire will become

Two wires A and B of same material and same mass have radius 2r and r . If resistance of wire A is 34 Omega , then resistance of B will be

" The resistance of a wire is "20Omega" .It is stretched so that the length becomes double,then the new resistance of the wire will b "

The resistance of a wire is 10 Omega . Its length is increased by 10% by stretching. The new resistance will now be

A wire of lenth L is drawn such that its diameter is reduced to half of its original diamter. If the initial resistance of the wire were 10 Omega , its new resistance would be