If R denotes circumradius, then in `DeltaABC,(b^2-c^2)/(2aR)` is equal to

If R denotes circumradius,then in Delta ABC,(b^(2)-c^(2))/(2aR) is equal to

If R denotes the circum-radius of a Delta ABC , then (b^(2)-c^(2))/(2aR) is equal to

Let R be the circumradius of DeltaABC . Then (b^(2)-c^(2))/(2aR) equals

In a DeltaABC,(a+c)/(a-c)tan(B/2) is equal to

In DeltaABC,2ac" sin "(A-B+C)/(2) is equal to

Let A(0,-1,1),B(0,0,1),C(1,0,1) are the vertices of a Delta ABC. If R and r denotes the circumradius and inradius of Delta ABC, then (r)/(R) has value equal to

In triangle A B C , let /_c=pi/2dot If r is the inradius and R is circumradius of the triangle, then 2(r+R) is equal to

In a DeltaABC, b cos^(2) C/2 + c cos^(2) B/2 is equal to

In triangle A B C , let /_c=pi/2dot If r is the inradius and R is circumradius of the triangle, then 2(r+R) is equal to (a) a+b (b) b+c (c) c+a (d) a+b+c