CH_(3)-CHO liAlH_(4)longrightarrow APCl_(3)longrightarrow B." Then 'B'is "

In a radioactive decay sequence A (lambda_(1))/(longrightarrow) B (lambda_(2))/(longrightarrow) C (lambda_(3))/ (longrightarrow) D What is the ratio of numbers of atoms of A to the number of atoms of B after long time interval starting with pure A .The mean lives of A and B are 20 hours and "30" minutes respectively

Cl_(2)+NaOH cold / dil longrightarrow A+ Nacl +H_(2) Cl_(2)+NaoH hot / conc longrightarrow B+Nacl+H_(2) of oxidation numbers of chlorine in A and B is

CH_(3)CHO + LiAlH_(4) to CH_(3)CH_(2)OH Nucleophite added in this reaction is

CH_(3)CHO + LiAlH_(4) to CH_(3)CH_(2)OH Nucleophile added in this reaction is

In the reaction CH_(3)COOHoverset(LiAlH_(4))rarrAoverset(PCl_(4))rarrBoverset(Alc.KCN)rarrC The product C is

In the reaction CH_(3)COOHoverset(LiAlH_(4))rarrAoverset(PCl_(4))rarrBoverset(Alc.KON)rarrC The product C is

Propene is allowed to react with m-chloroperoxybenzoic acid. The product (A) is then reduced with LiAlH_(4) in dry ether to give (B). CH_(3)CH=CH_(2)overset(MCPBA)rarrAunderset(2. H_(3)O^(+))overset(1. LiAlH_(4))rarrB The structure of the product (B) is :