If `sin theta = 3/4 and tan theta =9/2,` then `cos theta` is

If theta in the first quadrant and 5 tan theta =4 " then " ( 5 sin theta - 3 sin theta)/( sin theta + 2 cos theta) is equal to

If 2 - cos^(2) theta = 3 sin theta cos theta , sin theta ne cos theta then tan theta is

If 4 sin theta = 3 cos theta , " then " (sec^(2) theta )/( 4 ( 1 - tan^(2) theta )) is

If tan theta = (4)/(3) , then 3sin theta - 4 cos theta =

If tan theta = (4)/(3) , then 3sin theta - 4 cos theta =

If tan theta = (5)/(4) , then the value of ((3 sin theta + 4 cos theta)/(3 sin theta - 4 cos theta))^(2) is

If tan theta = 4/3 ,then the value of (3 sin theta + 2cos theta)/(3 sin theta - 2 cos theta) is

If cot theta= 3/4 , then sin theta+cos theta-tan theta is: यदि cot theta= 3/4 , है, तो sin theta+cos theta-tan theta का मान किसके बराबर होगा ?