`AB,A_(2)` and `B_(2)` are diatomic molecules. If the bond enthalpies of `A_(2), AB` and `B_(2)` are in the ratio `1:1:0.5` and the enthalpy of formation of `AB` from `A_(2)` and `B_(2)` is `-100kJ mol^(-1)` , what is the bond enthalpy of `A_(2)` ?

AB, A_2 and B_2 are diatomic molecules. If the bond enthalpies A_2 AB and B_2 are in the ratio 1:1:0.5 and the enthalpy of formation of AB fron A_2 and B_2 is -100 kJ mol^-1 , what is the bond enthalpy of A_2 :

AB, A_(2) and B_(2) are diatomic molecules.If the bond enthalpy of A_(2,) AB from A_(2) and B_(2) od -100 kJ//"mol" , what is the bond enthalpy of A_(2)" in" kJ//mol . ?

The standard bond dissociation energy of A_(2)(g),B_(2)(g) and AB(g) molecules are x, y and z kJ*mol^(-1) respectively. What will be the standard enthalpy of formation of AB(g)?

If the equilibrium constant for the reaction 2AB hArr A_(2) + B_(2) is 49 what is the value of equilibrium constant for AB hArr 1/2 A_(2) + 1/2 B_(2) ?

The energies of activation forward and revers reaction for A_(2)+B_(2)to2AB are 180 kJ mol^(-1) and 200 kJ mol^(-1) respectively. The pressure of a catalyst lowers the activation energy of both (forwar and reverse) reactions by 100 kJ mol^(-1) . The magnitude of enthalpy change of the reaction (A_(2)+B_(2)to2AB) in the presence of catalyst will be (in Kj mol^(-1) ):