The velocity of a body falling freely under gravitational field varies as `g^(p)h^(q)`, where g is gravitational acceleration and h is height from which the body is released. p and q are given by

The velocity of a body which has fallen under gravity varies as g^(a) h^(b) where g is the acceleration due to gravity at a place and h is the height through which the body has fallen, a and b are given by

Using the dimensional method, show that the velocity v of a body falling freely under gravity varies as sqrt"gh" where g is the acceleration due to gravity and h is distance through which the body falls.

The velocity of a body falling freely under acceleration due to gravity g varies as g^(p)h^(q) where h is decrease in height of the body. What are the values of p and q?

The velocity of a freely falling body changes as g^ph^q where g is acceleration due to gravity and h is the height. The values of p and q are

The velocity of a freely falling body changes as g^ph^q where g is acceleration due to gravity and h is the height. The values of p and q are

An object is falling freely under the gravitational force. Its velocity after travelling a distance h is v. If v depend upon gravitational acceleration g and distance h, prove with dimensional analysis v = k sqrt(gh) , where k is constant.

An object is falling freely under the gravitational force. Its velocity after travelling a distance his v. If v depends on gravitational accelertation g and distance h, then with the help of dimensional analysis, formula of v is ....... (k is constant)

A body falls freely under gravity from rest and reaches the ground in time t. Write an expression for the height fallen by the body.

A body released from rest to fall freely under gravity reaches the ground in 4 s. Then the height from which it is released is