" (i) "cos2x

6tan^(2)x-2cos^(2)x=cos2x if cos2x=

{x inR: cos2x+2cos^(2)x=2} =

Evaluate: (i) int(cos2x+2s epsilon^(2)x)/(cos^(2)x)dx (ii) int(2cos^(2)x-cos2x)/(s in^(2)x)dx

Evaluate: (i) int(cos2x+2s epsilon^(2)x)/(s in^(2)x)dx (ii) int(2cos^(2)x-cos2x)/(cos^(2)x)dx

Evaluate : (i) int (cos2x+2sin^2x)/(sin^2x)dx (ii) int(2cos^2x-cos2x)/(cos^2x)dx

Evaluate : (i) int(cos2x+2sin^(2)x)/(sin^(2)x)dx (ii) int(2cos^(2)x-cos2x)/(cos^(2)x)dx

If: (1- cos 2x)/(1+ cos 2x)=3 , then: x =

If the determinant |(cos2x, sin^2x,cos4x),(sin^2x , cos2x,cos^2x),(cos4x,cos^2x,cos2x)| is expanded in powers of sinx , then the constant term in the expansion is :