A magnifying glass is used, as the object to be viewed can be brought closer to the eye than the normal near point. This results in.

A magnifying galss is used, as the object to be viewed can be brought closer to the eye than the normal near point. This results in

For a normal eye, distance of near point from the eye is.

For a normal eye, distance of near point from the eye is.

For a normal eye, distance of near point from the eye is.

A converging lens of focal length 6.25 cm is used as magnifying glass. If the near point of the observer is 25 cm from the eye and the lens is held close to the eye, calculate the distance of the object from the lens

A converging lens of focal length 5.0 cm is used as a magnifying glass. The near point of the observer is 25 cm from the eye. If the lens is held close to the eye, find the distance of object from the lens and its angular magnification.

A converging lens of focal length 6.25 cm is used as a magnifying glass. If the near point of the observer is 25 cm from the eye and the lens is held close to the eye, calculate (i) the distance of the object from the lens and (ii) the angular magnification. Find the angular magnification when the final image is formed at infinity.

A magnifying glass is rated 6X for a normal relaxed eye. For a relaxed farsighted eye whose near point is 50 cm, then what will be its magnifying power?