" 3."4x+5y+2=0,3x+y+7=0

Given the four lines with the equations 'x+2y-3=0,3x+4y-7=0,2x+3y-4=0,4x+5y-6=0, then

The figure formed by the lines 2x+5y+4=0,5x+2y+7=0,2x+5y+3=0 and 5x+2y+6=0 is

Given four lines whose equations are x+2y-3=0,2x+3y-4=0,3x+4y-7=0 and 4x+5y-6=0 ,then the lines are

Two consecutive sides of a parallelogram are 4x+5y=0a d n7x+2y=0. If the equation of one diagonal is 11 x+7y=9, Equation of other diagonal : (A) 11x + 7y =0 (B) 3x - 5y + 5 = 0 (C) 7x + 11y = 0 (D) 3x + 5y + 5 =0

The lines 2 x+11 y-5=0,4 x-3 y-2=0 and 24 x+7 y-20=0

5x+7y+2=0 4x+6y+3=0

Given the four lines with the equations x+2y-3=0 , 3x+4y-7=0 , 2x+3y-4=0 , 4x+5y-6=0 , then

Given the four lines with the equations x+2y-3=0 , 3x+4y-7=0 , 2x+3y-4=0 , 4x+5y-6=0 , then

Given the four lines with equations x+2y-3=0, 3x+4y-7=0, 2x+3y-4=0 and 4x+5y-6=0 , then: