Commercially available conc. HCl contains 38% HCl by mass and has a density 1.19 g cm`""^(-3)`. Calculate the molarity of this HCI.

Explanation

38% HCl by mass contains 38 g of HCl in 100 g of solution.
Density =`("mass")/(" Volume")`
`1.19=(100 )/("volume")`
`therefore `Volume of 100 g of solution`= (100 )/(1.19 )`ml.
`therefore `Strength of solution `= (38 )/((100)/(1.19 ))xx 1000`
`=(38 xx 1.19 xx 1000 )/(100 ) gL^(-1)`
Molecular mass of HCI` = 36.5`
`therefore `Molarity of HCl `= (38 xx 1.19 xx 1000)/(100 xx 36.5)`
`=( 38 xx 11.9 )/( 36.5 ) =12.39`