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27.75 g of CaCl2, dissolved in 250 ml of...

27.75 g of `CaCl_2`, dissolved in 250 ml of solutions. Find molarity of chloride ions in this solution.

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`CaCI_2 hArr Ca^(2) +2CI^(-)`
formula Mass of `CaCI_2 = 111`
Molarity of `CI^(-)` ions `=(27.75 )/( 111xx (250 )/(1000 ) )xx2`
` =( 55 .5 xx 1000)/( 111xx 250 )`
`=2`
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