Calculate the mole fraction of `CH_3 OH` in a solution containing 30% by mass in water.

Explanation

Mass of `CH_3 OH = 30 g.`
Mass of water = 70 g
No. of moles of `CH_3 OH =(30)/(32) = 0.938`
No. of moles of `H_2O ==(70)/(18) = 3.89`
`X_(CH_3OH) = ( 0.938 )/(0.938 +3.89 _=(0.938 )/(4.83 )`