How many coulombs are required to produce 40.5 g of Al from molten `Al_(2)O_(3)`?

Explanation

`Al_(2)O_(3)hArr2Al^(3+)+3O^(2-)`
`Al^(3)+3etoAl`
`27g.3F`
27 g of Al is produced from electricity `=3xxF`
40.5 g of Al will be produced from electricity
`=(3F)/(27)xx40.5`
=4.5 F
`=4.5xx96500`
=434250 C