Find the sum of the zeroes of the quadratic polynomial `6x^(2)-3-7x`.

Answer

To find the sum of the zeroes of the quadratic polynomial \(6x^2 - 7x - 3\), we can follow these steps:

### Step 1: Identify the coefficients
The given polynomial is \(6x^2 - 7x - 3\). Here, we can identify the coefficients:
- \(a = 6\) (coefficient of \(x^2\))
- \(b = -7\) (coefficient of \(x\))
- \(c = -3\) (constant term)

### Step 2: Use the formula for the sum of the zeroes
The sum of the zeroes (denoted as \(\alpha + \beta\)) of a quadratic polynomial \(ax^2 + bx + c\) can be calculated using the formula:
\[ \alpha + \beta = -\frac{b}{a} \]

### Step 3: Substitute the values into the formula
Substituting the values of \(b\) and \(a\) into the formula:
\[ \alpha + \beta = -\frac{-7}{6} = \frac{7}{6} \]

### Step 4: Conclusion
Thus, the sum of the zeroes of the polynomial \(6x^2 - 7x - 3\) is:
\[ \frac{7}{6} \]