" Let "4 alpha int_(0)^(2)e^(-aH|)dx=5" then "alpha=

[" Let "4 alpha int_(-1)^(-)e^(-alpha|x|)dx=5" then "alpha=],[[" (A) "ln2," (B) "ln sqrt(2)],[" (C) "ln(3)/(4)," (D) "ln(4)/(3)]]

Let 4alpha int_(-1)^2 e^(-alpha|x|) dx = 5 , then alpha =

The value of alpha for which 4alphaint_(-1)^(2)e^(-alpha|x|)dx=5 is :

If I=int_(0)^(2)e^(x^(4))(x-alpha)dx=0 , then alpha lies in the interval-

If I=int_(0)^(2)e^(x^(4))(x-alpha)dx=0 , then alpha lies in the interval

If int_(0)^(1) x e^(x^(2) ) dx=alpha int_(0)^(1) e^(x^(2)) dx , then

If int_(0)^(1)e^(x^(2))(x-alpha)dx=0, then

If int_(0)^(1)e^(x^(2)) (x-alpha)dx=0 then

If int_(0)^(1) e^(x^(2))(x-alpha)dx=0 then

If int_(0)^(1)e^(x)-2(x-alpha)dx=0, then aly alpha<2(b)=alpha<0(c)=0