[(2)/(x)+(3)/(y)=(9)/(xy)],[(4)/(x)+(9)/(y)=(21)/(xy),w}]

Solve the following system of equations: (2)/(x)+(3)/(y)=(9)/(xy),quad (4)/(x)+(9)/(y)=(21)/(xy), where x!=0,y!=0

If (2)/(x) + (3)/(y) = (9)/( xy ) and (4)/(x) + (9)/(y) = (21)/(xy) where x ne 0 and y ne 0, that what is the value of x + y ?

Add the following (8)/(5)x+(11)/(7)y+(9)/(4)xy,-(3)/(2)x-(5)/(3)y-(9)/(5)xy

If x=4 and y=1, find the value of ((x)/(2)-(y)/(3))((x^(2))/(4)+(xy)/(6)+(y^(2))/(9)) .

If x=4 and y=1, find the value of ((x)/(2)-(y)/(3))((x^(2))/(4)+(xy)/(6)+(y^(2))/(9)) .

Multiply : 3 - (2)/(3)xy + (5)/(7)xy^(2) - (16)/(21)x^(2)y by -21 x^(2)y^(2)

(x^(2))/(4)-3xy^(3)+9y^(6)

Simplify: (x^(3)-y^(3))/(3x^(2)+9xy+6y^(2))xx(x^(2)+2xy+y^(2))/(x^(2)-y^(2))