8*3x+y+7=0" 4र "x-7y-5=0

The equations of the bisectors of the angles between the straight line 3x-4y+7=0 and 12x-5y-8=0 , are:

solve for x and y 2x-3y+7=0 3x+4y-5=0

Find the orthocentre of the triangle formed by 4x-7y+10=0, x+y-5=0, 7x+4y-15=0 .

The value of k for which the lines 7x -8y +5=0, 3x-4 y+5 =0 and 4x+5y+k =0 are concurrent is given by

The value of k for which the lines 7x -8y +5=0, 3x-4 y+5 =0 and 4x+5y+k =0 are concurrent is given by

The lines 3x+4y+7=0 and 4x+3y+5=0 are perpendicular.

Two consecutive sides of a parallelogram are 4x+5y=0 and 7x+2y=0. If the equation of one diagonal is 11 x+7y=9, Equation of other diagonal : (A) 11x + 7y =0 (B) 3x - 5y + 5 = 0 (C) 7x + 11y = 0 (D) x-y =0

The equation of straight line belonging to both the families of lines (x-y+1)+lambda_1(2x-y-2)=0 and (5x+3y-2)+lambda_2(3x-y-4)=0 where lambda_1, lambda_2 are arbitrary numbers is (A) 5x -2y -7=0 (B) 2x+ 5y - 7= 0 (C) 5x + 2y -7 =0 (D) 2x- 5y- 7= 0

The equation of straight line belonging to both the families of lines (x-y+1)+lambda_1(2x-y-2)=0 and (5x+3y-2)+lambda_2(3x-y-4)=0 where lambda_1, lambda_2 are arbitrary numbers is (A) 5x -2y -7=0 (B) 2x+ 5y - 7= 0 (C) 5x + 2y -7 =0 (D) 2x- 5y- 7= 0