A long narrow horizontal slit is placed 1 mm above a horizontal plane mirror. The interference between the light coming directly from the slit and that after reflection is seen on a screen 1.0 in away from the slit, Find the fringe-width if the light used has a wavelength of 700 nm.

A long narrow horizontal slit is placed 1 mm above a horizontal plane mirror. The interference between the light coming directly from the slit and that after reflection is seen on a screen 1.0 m away from the slit, Find the fringe-width if the light used has a wavelength of 700 nm.

A long horizontal slit is placed 1 mm above a horizontal plane mirror. The interference between the light coming directly from the slit and the after reflection is seen on a screen 1 m away from the slit. If the mirror reflects only 64% of the light falling on it, the ratio of the maximum to the minimum intensity in the interference pattern observed on the screen is

A long horizontal slit is placed 1 mm above a horizontal plane mirror. The interference between the light coming directly from the slit and the after reflection is seen on a screen 1 m away from the slit. If the mirror reflects only 64% of the light falling on it, the ratio of the maximum to the minimum intensity in the interference pattern observed on the screen is

A long narrow horizontal slit lies 1mm above a plane mirror.The interference pattern produced by the slit and its image is viewed on a screen distant 1m from the slit .The wavelength of light is 600nm .Find the distance of first maximum above the mirror.

A long narrow horizontal slit lies 1 mm above a plane mirror. The interference pattern produced by the slit and its and its image is viewed on a screen sum distance 1m from the slit. The wavelength of light is 600 nm . Then the distance of the first maxima above the mirror is equal to (d lt lt D) :

A long narrow horizontal slit lies 1 mm above a plane mirror. The interference pattern produced by the slit and its and its image is viewed on a screen sum distance 1m from the slit. The wavelength of light is 600 nm . Then the distance of the first maxima above the mirror is equal to (d lt lt D) :

In a Lloyds's mirror experiment as narrow slit S transmitting a light of wavelength lambda is placed 3 mm above a small plane mirror ( as shown). The light coming directly from the the slit and that coming after the reflection interfere on a screen placed at a distance of 90 cm from the slit. Length of mirror is 2 mm and the middle point of mirror is 2 mm from point P. If the mirror is shifted towards left then how does the fringe pattern on screen changes ?

A narrow slit S transmitting light of wavelength lamda is placed a distance d above a large plane mirror as shown in figure. The light coming directly from the slit and that coming after the reflection interference at a screen sum placed at a distance LD from the slit. a. What will be the intensity at a point just above the mirror. i.e., just above O? b. At what distance from O does the first maximum occur? ?