[" 9) "x=a(theta-sin theta)],[y=a(1+cos theta)],[" tin "(d^(2)y)/(ay^(2))" at "theta=x/2]

If x=a(theta-sin theta),y=a(1+cos theta),quad find (d^(2)y)/(dx^(2))

If x=a(theta-sin theta),y=a(1+cos theta) find (d^(2)y)/(dx^(2))

If x=a (theta-sin theta) and y=a(1-cos theta) , find (d^(2)y)/(dx^(2)) at theta=pi.

If x =theta -sin theta ,y=1-cos theta,then (d^(2)y)/(dx^(2))=

If x =a ( theta + sin theta), y =a (1 - cos thea) then (d ^(2) y)/(dx ^(2)) at theta = (pi)/(4) is

If x=a(theta+sin theta),y=a(1+cos theta), prove that (d^(2)y)/(dx^(2))=-(a)/(y^(2))

If [x= a{theta - sin(theta)] and [y= a{1 - cos (theta)] find [d^2y/dx^2 at (theta = pi/2)

If x=a(cos 2 theta+2 theta sin 2 theta) " and" y=a(sin 2 theta - 2 theta cos 2 theta) , find (d^(2)y)/(dx^(2)) " at" theta =(pi)/(8) .

If x=a(cos 2 theta+2 theta sin 2 theta) " and" y=a(sin 2 theta - 2 theta cos 2 theta) , find (d^(2)y)/(dx^(2)) " at" theta =(pi)/(8) .

x=a sin theta, y=a cos theta " then "x^2+y^2 =…………