If (-4,5) is a vertex of a square and one of its diagonal is 7x-y+8-0.Find the equation of other diagonal

The point (-4,5) is vertex of a square and one of its diagonal is 7x-y+8=0. The equation of other diagonal is

(-4,5) is a vertex of a square and one of its diagonals is 7x-y+8=0 . Find the equation of a the other diagonal.

The point (-4,5) is the vertex of a square and one of its diagonals is 7x-y+8=0. The equation of the other diagonal is :

The point (-4,5) is vertex of a square and one of its diagonal is 7x-y+8=0. The equation of other diagonal is 7x-y+23=0 7y+x+=30 7y+x=31 x-7y=30 x+7y+31=0

The point (-4,5) is vertex of a square and one of its diagonal is 7x-y+8=0. The equation of other diagonal is 7x-y+23=07y+x+=307y+x=31x-7y=30x+7y+31=0

A point (-4,5) is the vertex of a square and one of its diagonals is 7 x-y+8=0 . The equation of the other diagonals is

The co-ordinates of the vertex A of a square ABCD are (1, 2) and the equation of the diagonal BD is x+2y= 10 . Find the equation of the other diagonal and the co-ordinates of the centre of the square.